Απ: Πως μπορώ να δημιουργήσω δυναμικά ενα GridView ;

nicksop — Tue, 14 Mar 2006 22:45:10 GMT

Public Class DataGridTemplate

Implements ITemplate

Private columnName As String

Private ColumnType As String

Private TemplateType As ListItemType

Private WithEvents txt As TextBox

Private WithEvents btn As Button

' CONSTRUCTOR

Public Sub New(ByVal type As ListItemType, ByVal ColName As String, ByVal ColType As String)

TemplateType = type

Me.columnName = ColName

Me.ColumnType = ColType

End Sub

Private Sub InstantiateIn(ByVal container As Control) Implements ITemplate.InstantiateIn

txt = New TextBox

btn = New Button

Select Case TemplateType

Case ListItemType.Header

Case ListItemType.Item, ListItemType.AlternatingItem

txt.ID = "txtfield"

AddHandler container.DataBinding, AddressOf BindDataCtrl

container.Controls.Add(txt)

Case ListItemType.Footer

btn.Text = "Αποθηκευση"

' btn.ButtonType = ButtonColumnType.PushButton

container.Controls.Add(btn)

End Select

' AddHandler txt.TextChanged, AddressOf txtField_TextChanged

End Sub

Private Sub BindDataCtrl(ByVal sender As Object, ByVal e As EventArgs) Handles txt.DataBinding

Dim container As DataGridItem = CType(txt.NamingContainer, DataGridItem)

Dim str As String = (CType(container.DataItem, DataRowView))(columnName).ToString()

txt.Text = DataBinder.Eval(container.DataItem, columnName)

End Sub

Πισω στο κωδικα απλως γραφεις :

Dim tc As New TemplateColumn

tc.ItemTemplate = New DataGridTemplate(ListItemType.Item, "Column1", "String")

tc.HeaderText = "Column1"

tc.HeaderStyle.Width = 100

DataGrid.Columns.Add(tc)

DataBind()

Πως μπορώ να δημιουργήσω δυναμικά ενα GridView ;

nicksop — Sat, 11 Mar 2006 03:00:08 GMT

Θα ήθελα να φίαξω δημιουργήσω δυναμικά ενα GridView με DataBound Columns χωρις να χρησιμοποιοησω το design

π.χ.

Dim field As New TemplateField()

field.HeaderText = "EmployeeId"

GridView1.Columns.Add(field)

θα βοήθουσε οποιαδηποτε ιδέα με κώδικα!!

Ευχαριστω!

ASP.NET WebForms

Απ: Πως μπορώ να δημιουργήσω δυναμικά ενα GridView ;

Πως μπορώ να δημιουργήσω δυναμικά ενα GridView ;